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A metallic sheet is of rectangular shape with dimensions 48 m × 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m 3) is : (M.A.T. 2003)
To determine the volume of a sphere, you have to take the diamater to the power of 3 and multiply it to Pi as well as 1/6. A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m 3) is: A. 4830. B. 8960. C. 5120. D. 6420 If a metallic cuboid weight 16 kg .
Data. Decagon. Decimal Place. Diameter. Divide. Division. East 9 t 16 Kg. F). Change the following to tonnes (t) and A uniform beam, AB, is 6 m long and has a weight of 240 N. Initially 4.2 is made of uniform sheet metal with cross-section the frame shown in Fig. A box is to be assembled in the shape of the cuboid shown in Fig. 3.1.
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Volume of the cuboid is L×B ×H = LBH. 16kg = kLBH ⋯(1) All the dimensions are reduced to one-Fourth. l = 4L. it weighs 0.25 kg. Step-by-step explanation: Let original dimensions be L, B and H. Volume of cuboid = LBH => 16 kg = LBH. All dimensions are reduced to one fourth ( given ) l = L/4. b = B/4. h = H/4. New weight : => L/4 × B/4 × H/4 => LBH × 1/64 => 16/64 => 0.25 kg.
m = 7.5 ⋅ 100 π ⋅ ( 1 1 2 − ( 11 − 1) 2) / 1000 = 49.48 kg. m= 7.5⋅ 100π⋅ (112 −(11−1)2)/1000 =49.48 kg. Try another example. We would be pleased if You send us any improvements of this math problem. Thank you! Problem with corrections: The thickness of a metallic tube is 1cm, and its outer radius is 11cm.
From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m 3) is: A. 4830. B. 8960. C. 5120. D. 6420 If a metallic cuboid weight 16 kg . how much would a miniature cuboid of metal weight if all dimensions are reduced to one-fourth of the original ?
The volume of a cuboid is calculated by multiplying the length by the width and the height of the cuboid. If 1 cubic cm of iron weighs 15 gms. Find the weight of the empty box in kg. Solution: The external length of iron = 36 cm.
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l = 4L. it weighs 0.25 kg. Step-by-step explanation: Let original dimensions be L, B and H. Volume of cuboid = LBH => 16 kg = LBH. All dimensions are reduced to one fourth ( given ) l = L/4. b = B/4. h = H/4. New weight : => L/4 × B/4 × H/4 => LBH × 1/64 => 16/64 => 0.25 kg.
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The total length of all edges of the cuboid. Face Area Af The size of each face of the cuboid. For a perfect cube, all three faces will be the same, but for an irregular cuboid, there will be three different values. Opposite sides will always be identical. Total Surface Area At The surface area of all six faces of the Cuboid added together.
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If a metallic cuboid weight 16 kg . how much would a miniature cuboid of metal weight if all dimensions are reduced to one-fourth of the original ? A. 0.25 kg B. 0.50 kg
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